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4.5 Sine and Cosecant Function

SOLUTIONS
1a



1b



1c



2a



2b



2c



2d



3a



3b



3c



3d



4



5



6a



6b



7a



7b



8



9



10a



10b





Why did you draw the vertex

Submitted by KevinChin (not verified) on Thu, 01/26/2012 - 23:42.
Why did you draw the vertex of the reciprocal graph at .5. Shouldn't it be 2?

no it should be at 0.5

Submitted by admin (not verified) on Fri, 01/27/2012 - 01:12.
no it should be at 0.5 Kevin. since $\csc(\frac{\pi}{2}) = 1$ it makes sense that $\frac{1}{2}\csc(\frac{\pi}{2}) = \frac{1}{2}$ no? Min

yeah but in the polynomial

Submitted by KevinChin (not verified) on Fri, 01/27/2012 - 01:18.
yeah but in the polynomial functions videos where you draw the reciprocals, if there is a point on the y value thats 1/2, the vertex of the reciprocal becomes 2 or if its 0.1 then it becomes 10. Is this different from a reciprocal trig graph?

you have to understand, only

Submitted by admin (not verified) on Fri, 01/27/2012 - 01:21.
you have to understand, only $\sin(\frac{\pi}{2})$ is flipped up side down. So, $\frac{1}{2}\csc(\frac{\pi}{2})$ means, flip ONLY $\sin(\frac{\pi}{2})$----> which is still 1.... then times by $\frac{1}{2}$. You are thinking.. multiply $\frac{1}{2}$ by $\sin(\frac{\pi}{2})$ then you flip that... which is incorrect order. Min

Which question are you

Submitted by admin (not verified) on Fri, 01/27/2012 - 00:55.
Which question are you referring to Kevin? Min

10 (a) (b) and the reciprocal

Submitted by KevinChin (not verified) on Fri, 01/27/2012 - 01:03.
10 (a) (b) and the reciprocal function questions in 4.6.

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