Lectures and Quick Notes(1.4)
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Chapter 1
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Lectures and Quick Notes(1.4
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Lectures/Notes 4 Videos

Introduction to Elimination Method

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Section Intro

Introduction of elimination method ex1

ex Solve for (x, y) such that

\displaystyle \begin{cases} 2x + y = 3\\ x - y = -2 \end{cases}

Therefore, (x, y) = (\dfrac{1}{3}, \dfrac{7}{3})

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Introduction of elimination method ex1

Elimination ex2

ex Solve for (x, y) such that

\displaystyle \begin{cases} 2x - 5y = 11\\ 5x + 2y = -2 \end{cases}

Therefore, (x, y) = (\dfrac{12}{29}, -\dfrac{59}{29}).

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Elimination ex2

Elimination ex3

ex Solve for (x, y) such that

\displaystyle \begin{cases} ax -3y = 3 \\ 2x + by = 12 \end{cases}

Therefore, \dfrac{a(b + 12)}{ab + 6} - 3 = y.

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Elimination ex3