11. Q11f
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Similar Question 1
<p>Solve by elimination.</p><p><code class='latex inline'>\displaystyle x-y=6\\\frac{2 x}{3}+\frac{y}{3}=1 </code></p>
Similar Question 2
<p>Solve by elimination.</p><p><code class='latex inline'>\displaystyle x-y=6\\\frac{2 x}{3}+\frac{y}{3}=1 </code></p>
Similar Question 3
<p>Solve the linear system. Choose a method and explain why you chose that method. Check the solution.</p><p><code class='latex inline'>\begin{array}{c} 6x-5y=-1\\ 5x-4y=-1 \end{array}</code></p>
Similar Questions
Learning Path
L1 Quick Intro to Factoring Trinomial with Leading a
L2 Introduction to Factoring ax^2+bx+c
L3 Factoring ax^2+bx+c, ex1
Now You Try
<p>Simplify and then solve each linear system.</p><p><code class='latex inline'>\displaystyle \begin{array}{lllll} &x + y = 40\\ &\frac{x}{20}- \frac{y}{5} =1 \end{array} </code></p>
<p>Solve for (x, y)</p><p><code class='latex inline'>\displaystyle \begin{array}{lllll} & \frac{x}{2} - \frac{2y}{3} = \frac{7}{3} \\ & \frac{3x}{2} + 2y = 5 \end{array} </code></p>
<p> Determine the point of intersection for each pair of lines. Verify your solution. </p><p><code class='latex inline'> \displaystyle \begin{array}{ccccc} &\frac{1}{2}x - 5 y = 7\\ &3x + \frac{y}{2} = \frac{23}{2} \\ \end{array} </code></p>
<p> Determine the point of intersection for each pair of lines. Verify your solution. </p><p><code class='latex inline'> \displaystyle \begin{array}{ccccc} &\frac{x}{9} + \frac{y -3}{3} = 1 \\ & \frac{x}{2} - (y + 9) = 0\\ \end{array} </code></p>
<p>Solve by elimination.</p><p><code class='latex inline'>\displaystyle \frac{4 a}{3}-\frac{b}{4}=9\\\frac{5 a}{6}+b=1 </code></p>
<p>Tell whether the system has one solution, infinitely many solutions, or no solution.</p><p><code class='latex inline'>\displaystyle 4 x-8 y=15\\-5 x+10 y=-30 </code></p>
<p>Find the value of x and y which satisfies</p><p><code class='latex inline'>x - y = 9</code> and <code class='latex inline'>y = -x + 3</code></p>
<p>Solve the linear system. Choose a method and explain why you chose that method. Check the solution.</p><p><code class='latex inline'>\begin{array}{c} 6x-5y=-1\\ 5x-4y=-1 \end{array}</code></p>
<p> Determine the point of intersection for each pair of lines. Verify your solution. </p><p><code class='latex inline'> \displaystyle \begin{array}{ccccc} &\frac{x}{9} + \frac{y -3}{3} = 1 \\ & \frac{x}{2} - (y + 9) = 0\\ \end{array} </code></p>
<p> Determine the point of intersection for each pair of lines. Verify your solution. </p><p><code class='latex inline'> \displaystyle \begin{array}{ccccc} &\frac{x}{11} - \frac{y}{8} = -2 \\ &\\ &\frac{x}{2} -\frac{y}{4} = 3\\ \end{array} </code></p>
<p>Solve by elimination.</p><p><code class='latex inline'>\displaystyle \frac{x}{3}-\frac{y}{2}=-3 </code></p><p><code class='latex inline'>\displaystyle \frac{x}{6}+\frac{y}{5}=3 </code></p>
<p><code class='latex inline'>\displaystyle \begin{aligned} x+y &=0 \\ 3 x-2 y &=10 \end{aligned} </code></p><p>Which of the following ordered pairs <code class='latex inline'> (x, y) </code> satisfies the system of equations above?</p><p><code class='latex inline'>\displaystyle (3,-2) </code></p><p><code class='latex inline'>\displaystyle (2,-2) </code></p><p><code class='latex inline'>\displaystyle (-2,2) </code></p><p><code class='latex inline'>\displaystyle (-2,-2) </code></p>
<p>Solve by elimination.</p><p><code class='latex inline'>\displaystyle \frac{x}{3}+\frac{y}{4}=2 </code></p><p><code class='latex inline'>\displaystyle \frac{2 x}{3}-\frac{y}{2}=0 </code></p>
<p>Solve by elimination.</p><p><code class='latex inline'>\displaystyle x-y=6\\\frac{2 x}{3}+\frac{y}{3}=1 </code></p>
<p>Solve by elimination.</p><p><code class='latex inline'>\displaystyle \frac{x}{3}-\frac{y}{6}=-\frac{2}{3}\\\frac{x}{12}-\frac{y}{4}=1 \frac{1}{2} </code></p>
<p>Solve by elimination.</p><p><code class='latex inline'>\displaystyle \frac{1}{3} m-\frac{1}{6} n=\frac{1}{2}\\\frac{m}{5}-\frac{3 n}{10}=\frac{1}{2} </code></p>
<p> Determine the point of intersection for each pair of lines. Verify your solution. </p><p><code class='latex inline'> \displaystyle \begin{array}{ccccc} &\frac{x}{11} - \frac{y}{8} = -2 \\ &\\ &\frac{x}{2} -\frac{y}{4} = 3\\ \end{array} </code></p>
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